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Primera parte &   V8 Contenidos     B1.- Concepto de equilibrio qumico. 1.1.Caractersticas. Aspecto dinmico de las reacciones qumicas. 2.-Ley de accin de masas. KC. 3.-Grado de disociacin a. 3.1. Relacin KC con a. 4.- Kp. Relacin con Kc 4.1. Magnitud de las constantes de equilibrio. 5.-Cociente de reaccin. 6.-Modificaciones del equilibrio. Principio de Le Chatelier. 6.1.Concentracin en reactivos y productos. 6.2.Cambios de presin y temperatura. 6.3.Principio de Le Chatelier. 6.4.Importacia en procesos industriales. 7.-Equilibrios heterogneos.%PDlP=PPP1PXPPP&"&&&'>"&'"*"&'""&' "*""&'*"*"*"&'*" &  #  "  &  ' : "  &  ' ( "  &  ' " "  &  '  "  &  ' % "  &  '  " 6)  2    2       4                 Qu es un equilibrio qumico?  .Es una reaccin que nunca llega a completarse, pues se produce en ambos sentidos (los reactivos forman productos, y a su vez, stos forman de nuevo reactivos). Cuando las concentraciones de cada una de las sustancias que intervienen (reactivos o productos) se estabiliza se llega al EQUILIBRIO QUMICO.2/ / 5&REquilibrio de molculas (H2 + I2 2 HI)F* * 4$xVariacin de la concentracin con el tiempo (H2 + I2 2 HI)P=. = X90Reaccin: H2 + I2 2 HI^ $ $$ $$($  Constante de equilibrio (Kc)$&   En una reaccin cualquiera: a A + b B c C + d D la constante Kc tomar el valor: para concentraciones en el equilibrio La constante Kc cambia con la temperatura ATENCIN!: Slo se incluyen las especies gaseosas y/o en disolucin. Las especies en estado slido o lquido tienen concentracin constante y por tanto, se integran en la constante de equilibrio.UPZ0Z0Z0ZZ(   :"nV (      : ~  Z:Constante de equilibrio (Kc)$&    En la reaccin anterior: H2(g)+ I2(g) 2 HI (g) El valor de KC, dada su expresin, depende de cmo se ajuste la reaccin. Es decir, si la reaccin anterior la hubiramos ajustado como: H2(g) + I2(g) HI (g), la constante valdra la raz cuadrada de la anterior. "1 7b&      ?  \;Ejemplo: Tengamos el equilibrio: 2 SO2(g) + O2(g) 2 SO3(g). Se hacen cinco experimentos en los que se introducen diferentes concentraciones iniciales de ambos reactivos (SO2 y O2). Se produce la reaccin y una vez alcanzado el equilibrio se miden las concentraciones tanto de reactivos como de productos observndose los siguientes datos:T f   u    K  En la reaccin anterior: 2 SO2(g) + O2(g) 2 SO3(g) KC se obtiene aplicando la expresin: y como se ve es prcticamente constante. #*T+   '  )  ^<Ejercicio A: Escribir las expresiones de KC para los siguientes equilibrios qumicos: a) N2O4(g) 2 NO2(g); b) 2 NO(g) + Cl2(g) 2 NOCl(g); c) CaCO3(s) CaO(s) + CO2(g); d) 2 NaHCO3(s) Na2CO3(s) + H2O(g) + CO2(g).   -                  a) b)  c) d)  6%Significado del valor de Kc$&    :Ejemplo: En un recipiente de 10 litros se introduce una mezcla de 4 moles de N2(g) y 12 moles de H2(g); a) escribir la reaccin de equilibrio; b) si establecido ste se observa que hay 0,92 moles de NH3(g), determinar las concentraciones de N2 e H2 en el equilibrio y la constante Kc. fG   3%38 (  "   a) Equilibrio: N2(g) + 3 H2(g) 2 NH3(g) Moles inic.: 4 12 0 Moles equil. 4  0,46 12  1,38 0,92 b) 3,54 10,62 0,92 conc. eq(mol/l) 0,354 1,062 0,092 [NH3]2 0,0922 M2 Kc =      =        = 1,996 10 2 M 2 [H2]3 [N2] 1,0623 0,354 M4 RZ{P3 33 333333Y373    333333     #    $  O     d=Ejercicio B: En un recipiente de 250 ml se introducen 3 g de PCl5, establecindose el equilibrio: PCl5(g) PCl3 (g) + Cl2(g). Sabiendo que la KC a la temperatura del experimento es 0,48, determinar la composicin molar del equilibrio..  4 %    Z X  0  "    B Equilibrio: PCl5(g) PCl3(g) + Cl2(g) Moles inic.: 3/208,2 0 0 Moles equil. 0,0144  x x xP     P          .  -  Constante de equilibrio (Kp)$&   rEn las reacciones en que intervengan gases es mas sencillo medir presiones parciales que concentraciones: a A + b B c C + d D y se observa la constancia de Kp viene definida por: %3?    $v  B  Constante de equilibrio (Kp)$&   En la reaccin vista anteriormente: 2 SO2(g) + O2(g) 2 SO3(g) p(SO3)2 Kp =        p(SO2)2 p(O2) De la ecuacin general de los gases: p V = n RT se obtiene: n p = R T = concentracin R T V [SO3]2 (RT)2 Kp =           = Kc (RT) 1 [SO2]2 (RT)2 [O2] (RT)  AZFp<2?Zp<2Z)        l        X6        +Constante de equilibrio (Kp) (continuacin)$,&   vVemos, pues, que KP puede depender de la temperatura siempre que haya un cambio en el n de moles de gases pcc pDd [C]c (RT)c [D]d (RT)d Kp =     =           = pAa pBb [A]a (RT)a [B]b (RT)b en donde Dn = incremento en n de moles de gases (nproductos  nreactivos)fkZ<<pZFKpZF2 W       (  @v      Ejemplo: Calcular la constante Kp a 1000 K en la reaccin de formacin del amoniaco vista anteriormente. (KC = 1,996 10 2 M 2)  f  I      $  $&  `  N2(g) + 3 H2(g) 2 NH3(g) Dn = nproductos  nreactivos = 2  (1 + 3) =  2 KP = Kc (RT)Dn = L2 atmL  2 1,996 10 2   0,082    1000K = mol2 mol K Kp = 2,97 10 6 atm 2 eP[p<2)P   33 3333r  ?    Y   I5Ejercicio C: La constante de equilibrio de la reaccin: N2O4 2 NO2 vale 0,671 a 45C . Calcule la presin total en el equilibrio en un recipiente que se ha llenado con N2O4 a 10 atmsferas y a dicha temperatura. Datos: R = 0,082 atmlmol-1K-1.  ,  $ h  B  $=   De la ecuacin de los gases podemos deducir: p 10 atm mol K [N2O4]inic. =    =          = 0, 38 M R T 0,082 atmL 318 K Equilibrio: N2O4 2 NO2 conc. Inic. (M) 0,38 0 conc. Equil. (M) 0,38  x 2x [NO2]2 4x2 Kc =    =     = 0,671 x = 0,18 [N2O4] 0,38  x `-Zhp<2]Z`p<2H   D    ;       9    g        s K7Ejercicio C (cont): La constante de equilibrio de la reaccin: N2O4 2 NO2 vale 0,671 a 45C . Calcule la presin total en el equilibrio en un recipiente que se ha llenado con N2O4 a 10 atmsferas y a dicha temperatura. Datos: R = 0,082 atmlmol-1K-1. ,  $ h  B  >   3   Equilibrio: N2O4 2 NO2 conc. Inic. (M) 0,38 0 conc. Equil. (M) 0,20 0,36 pTOTAL = ([N2O4]eq + [NO2]eq)RT = 0,082 atmL (0,20 M + 0,36 M)      318 K = 14,6 atm mol KUPqp<2    9 33          (  = Magnitud de Kc y Kp.@ @      (El valor de ambas constantes puede variar entre lmites bastante grandes: H2(g) + Cl2(g) 2 HCl (g) Kc (298 K) = 2,5 1033 La reaccin est muy desplazada a la derecha. H2(g) + I2(g) 2 HI(g) Kc (698 K) = 55,0 Se trata de un verdadero equilibrio. N2(g) + O2(g) 2 NO (g) Kc (298 K) = 5,3 10 31 La reaccin est muy desplazada a la izquierda, es decir, apenas se forman productos.ZK       -    $       VT[  e  U  } 2Grado de disociacin (a).$  Se utiliza en aquellas reacciones en las que existe un nico reactivo que se disocia en dos o ms. Es la fraccin de un mol que se disocia (tanto por 1). En consecuencia, el % de sustancia disociada es igual a 100 a.$   XEjemplo: En un matraz de 5 litros se introducen 2 moles de PCl5(g) y 1 mol de de PCl3(g) y se establece el siguiente equilibrio: PCl5(g) PCl3(g) + Cl2(g). Sabiendo que Kc (250 C) = 0,042; a) cules son las concentraciones de cada sustancia en el equilibrio?; b) cul es el grado de disociacin? - f)   0 $   fFf#$   a) Equilibrio: PCl5(g) PCl3(g) + Cl2(g) Moles inic.: 2 1 0 Moles equil. 2 x 1 + x x conc. eq(mol/l)(2 x)/5 (1 + x)/5 x/5 [PCl3] [Cl2] (1+x)/5 x/5 Kc =       =       = 0,042 [PCl5] (2 x)/5 De donde se deduce que x = 0,28 moles/PZt0<2&Zf        30      $  (     !hEjemplo (cont.): En un matraz de 5 litros se introducen 2 moles de PCl5(g) y 1 mol de de PCl3(g) y se establece el siguiente equilibrio: PCl5(g) PCl3(g) + Cl2(g). Sabiendo que Kc (250 C) = 0,042; a) cules son las concentraciones de cada sustancia en el equilibrio?; b) cul es el grado de disociacin? 5 f)   0 $   fFf#$   >[PCl5] = (2 0,28)/5 = 0,342 mol/l [PCl3] = (1+ 0,28)/5 = 0,256 mol/l [Cl2] = 0,28 /5 = 0,056 mol/l b) Si de 2 moles de PCl5 se disocian 0,28 moles en PCl3 y Cl2, de cada mol de PCl5 se disociarn 0,14. Por tanto, a = 0,14, lo que viene a decir que el PCl5 se ha disociado en un 14 %.  3   3  3f     3 Zz      h ",Relacin entre Kc y a.6&    Sea una reaccin A B + C. Si llamamos  c = [A]inicial y suponemos que en principio slo existe sustancia  A , tendremos que: Equilibrio: A B + C Conc. Inic. (mol/l): c 0 0 conc. eq(mol/l) c(1 a) c a c a [B] [C] c a c a c a2 Kc =     =      =    [A] c (1 a) (1 a) En el caso de que la sustancia est poco disociada (Kc muy pequea): a << 1 y Kc @ c a2Z0<2OZ0Z2    HX     +  8               (TEjemplo: En un matraz de 5 litros se introducen 2 moles de PCl5(g) y 1 mol de de PCl3(g) y se establece el siguiente equilibrio:PCl5(g) PCl3(g) + Cl2(g). Sabiendo que Kc (250 C) = 0,042 a) cules son las concentraciones de cada sustancia en el equilibrio?; b) cul es el grado de disociacin?+ f7  . $   fFf#Z<        .a) Equilibrio: PCl5(g) PCl3(g) + Cl2(g) Conc. inic.: 2/5 1/5 0 conc. eq(mol/l) 0,4(1 a) 0,2+0,4 a 0,4 a [PCl3] [Cl2] (0,2+0,4 a) 0,4 a Kc =       =          = 0,042 [PCl5] 0,4(1 a) b) En este caso y dado el valor de la constante no debe despreciarse a frente a 1, por lo que deberamos resolver el sistema: a = 0,14/PUZ}p<2Pf    =     3fCH 3t         : ,Ejercicio D: En el equilibrio anterior (Kc = 0,042): PCl5(g) PCl3(g) + Cl2(g) cul sera el grado de disociacin y las concentraciones en el equilibrio de las tres sustancias si pusiramos nicamente 2 moles de PCl5(g) en los 5 litros del matraz?     $   !@(      2Equilibrio: PCl5(g) PCl3(g) + Cl2(g) Conc. inic.: 2/5 0 0 conc. eq(mol/l) 0,4(1 a) 0,4 a 0,4 a [PCl3] [Cl2] 0,4 a2 Kc =       =     = 0,042 [PCl5] (1 a) En este caso y dado el valor de la constante no debe despreciarse a frente a 1, por lo que deberamos resolver el sistema: a = 0,276Zi0<2Z      E      .EG 3           / -Ejercicio D (cont.): En el equilibrio anterior (Kc = 0,042): PCl5(g) PCl3(g) + Cl2(g) cul sera el grado de disociacin y el nmero de moles en el equilibrio de las tres sustancias si pusiramos nicamente2 moles de PCl5(g) en los 5 litros del matraz?   $     @1      Como a = 0,276 [PCl5] = 0,4 mol/l (1 0,276) = 0,29 mol/l [PCl3] = 0,4 mol/l 0,276 = 0,11 mol/l [Cl2] = 0,4 mol/l 0,276 = 0,11 mol/l n(PCl5) = 0,29 mol/l 5 l = n(PCl3) = 0,11 mol/l 5 l = n(Cl2) = 0,11 mol/l 5 l = PP   @    4 E1REjercicio E: A 450 C y 10 atm de presin el NH3 (g) est disociado en un 95,7 % segn la reaccin: 2 NH3 (g) N2 (g) + 3 H2 (g). Calcular KC y KP a dicha temperatura.   # 6 $    &    2 NH3 (g) N2 (g) + 3 H2 (g) n inic. (mol) n 0 0 n equil. (mol) n(1 a) na/2 3na/2 0,043 n 0,4785 n 1,4355 n ntotal = 0,043 n + 0,4785 n + 1,4355 n = 1,957 n La presin parcial depende de la fraccin molar n(NH3) 0,043 n p(NH3) =     ptotal =       10 atm = 0,22 atm ntotal 1,957 n Anlogamente: p(N2) = (0,4785/1,957) 10 atm = 2,445 atm p(H2) = (1,4355 /1,957) 10 atm = 7,335 atm. &Znp<2gZp<-  b  & $ %J  W       ^           G3`Ejercicio E (cont.): A 450 C y 10 atm de presin el NH3 (g) est disociado en un 95,7 % segn la reaccin: 2 NH3 (g) N2 (g) + 3 H2 (g). Calcular KC y KP a dicha temperatura. # 6 (    &#   rp(NH3) = 0,22 atm; p(N2) = 2,445 atm; p(H2) = 7,335 atm. p(H2)3 p(N2) (7,335 atm)3 2,445 atm Kp =      =            = p(NH3)2 (0,22 atm)2 KP = 1,99104atm2 KP 1,99104 atm2 KC=    =              = 5,66 M2 (RT)2 (0,082 atmM 1 K 1)2 (723 K)2 <p<-                 3333    33          "        F2 Tambin puede resolverse: 2 NH3 (g) N2 (g) + 3 H2 (g) Conc inic. (M) c 0 0 Conc. Equil. (M) c (1 a) ca/2 3ca/2 0,043 c 0,4785 c 1,4355 c La presin total depende del n de moles total y por tanto de la concentracin total: ctotal = 0,043 c + 0,4785 c + 1,4355 c = 1,957 c Aplicando la ley de los gases: ctotal = p / R T ctotal =10 atm / (0,082 atml/molK) 723K = 0,169 M c = ctotal/ 1,957 = 0,086 M [NH3] = 0,043 0,086 M = 3,7 10 3 M Igualmente [N2] = 4,1 10 2 M y [H2] = 0,123 M [H2]3 [N2] (0,123 M)3 4,1 10 2 M Kc =      =           = 5,6 M2 [NH3]2 (3,7 10 3 M)2 KP = Kc(RT)Dn = 5,6 M2 (0,082 atmM 1K 1 723 K) 2 = 2,0 104 atm2ZWPrp<2Jp<-  J #          333      3333f    J               < #Cociente de reaccin (Q)  En una reaccin cualquiera: a A + b B c C + d D se llama cociente de reaccin a: Tiene la misma frmula que la Kc pero a diferencia que las concentraciones no tienen porqu ser las del equilibrio. zUZZvPZ(0T&w  U $ Cociente de reaccin (Q) (cont.) ! Si Q = Kc entonces el sistema est en equilibrio. Si Q < Kc el sistema evolucionar hacia la derecha, es decir, aumentarn las concentraciones de los productos y disminuirn las de los reactivos hasta que Q se iguale con Kc. Si Q > Kc el sistema evolucionar hacia la izquierda, es decir, aumentarn las concentraciones de los reactivos y disminuirn las de los productos hasta que Q se iguale con Kc )    t  0       %.Ejemplo: En un recipiente de 3 litros se introducen 0,6 moles de HI, 0,3 moles de H2 y 0,3 moles de I2 a 490C. Si Kc = 0,022 a 490C para 2 HI(g) H2(g) + I2(g) a) se encuentra en equilibrio?; b) Caso de no encontrarse, cuantos moles de HI, H2 e I2 habr en el equilibrio?  fK    (  ff0  @t      a) [H2] [I2] 0,3/3 0,3/3 Q =       =       = 0,25 [HI]2 (0,6/3)2 Como Q > Kc el sistema no se encuentra en equilibrio y la reaccin se desplazar hacia la izquierda.><k<e <f   *     3333 31&u  Z &>Ejemplo (cont.): En un recipiente de 3 litros se introducen 0,6 moles de HI, 0,3 moles de H2 y 0,3 moles de I2 a 490C. Si Kc = 0,022 a 490C para 2 HI(g) H2(g) + I2(g) a) se encuentra en equilibrio?; b) Caso de no encontrarse, cuantos moles de HI, H2 e I2 habr en el equilibrio?   fK    (  ff0  @|     b) Equilibrio: 2 HI(g) I2(g) + H2(g) Moles inic.: 0,6 0,3 0,3 Moles equil. 0,6 + 2 x 0,3  x 0,3  x 0,6 + 2 x 0,3  x 0,3  x conc. eq(mol/l)             3 3 3 Pip<2Pf    Z  $  +   'aEjemplo (cont.): b) Caso de no encontrarse, cuantos moles de HI, H2 e I2 habr en el equilibrio?jb ff0   b  0,3  x 0,3  x       3 3 Kc =          = 0,022 0,6 + 2 x 2     3 Resolviendo se obtiene que: x= 0,163 moles Equil: 2 HI(g) I2(g) + H2(g) Mol eq: 0,6+20,163 0,3 0,163 0,3 0,163 n(HI) = 0,93 mol n(I2) = 0,14 mol n(H2) = 0,14 mol0<<Z0Z?ZG   G   3333 3  C      ,  7 )Modificaciones del equilibrio    Si un sistema se encuentra en equilibrio (Q = Kc) y se produce una perturbacin: Cambio en la concentracin de alguno de los reactivos o productos. Cambio en la presin (o volumen) Cambio en la temperatura. El sistema deja de estar en equilibrio y trata de volver a l.HQ~?/!~?&.   +CCambio en la concentracin de alguno de los reactivos o productos. DB( D Si una vez establecido un equilibrio se vara la concentracin algn reactivo o producto el equilibrio desaparece y se tiende hacia un nuevo equilibrio. Las concentraciones iniciales de este nuevo equilibrio son las del equilibrio anterior con las variaciones que se hayan introducido. Lgicamente, la constante del nuevo equilibrio es la misma, por lo que si aumenta [ reactivos], Q y la manera de volver a igualarse a KC sera que [ reactivos] (en cantidades estequiomtricas) y, en consecuencia, que [productos] . ~& E$X   :(Ejemplo: En el equilibrio anterior: PCl5(g) PCl3(g) + Cl2(g) ya sabemos que partiendo de 2 moles de PCl5(g) en un volumen de 5 litros, el equilibrio se consegua con 1,45 moles de PCl5, 0,55 moles de PCl3 y 0,55 moles de Cl2 cuntos moles habr en el nuevo equilibrio si una vez alcanzado el primero aadimos 1 mol de Cl2 al matraz? (Kc = 0,042) ^ f  (  . L a    &%  5 Equilibrio: PCl5(g) PCl3(g) + Cl2(g) Moles inic.: 1,45 0,55 1,55 Moles equil. 1,45 + x 0,55  x 1,55 x 1,45 + x 0,55  x 1,55 x conc. eq(mol/l)             5 5 5 Pd0<2P    Z     0   .  0,55  x 1,55 x        5 5 Kc =          = 0,042 1,45 + x     5 Resolviendo: x = 0,268 Equilibrio: PCl5(g) PCl3(g) + Cl2(g) neq (mol) 1,45+0,268 0,55 0,268 1,55 0,268 1,718 0,282 1,282 conc (mol/l) 0,3436 0,0564 0,2564 El equilibrio se ha desplazado a la izquierda. Se puede comprobar como: 0,0564 M 0,2564 M          = 0,042 0,3436 M p<2IP~p<2IP;0<2E  5       3t       K   0 !Cambio en la presin (o volumen) " PEn cualquier equilibrio en el que haya un cambio en el nmero de moles entre reactivos y productos como por ejemplo : A B+ C (en el caso de una disociacin es un aumento del nmero de moles) ya se vio que Kc @ c a2 Al aumentar  p (o disminuir el volumen) aumenta la concentracin y eso lleva consigo una menor  a , es decir, el equilibrio se desplaza hacia la izquierda que es donde menos moles hay.X  bY  1!0Cambio en la presin (o volumen) (continuacin) 1 Este desplazamiento del equilibrio hacia donde menos moles haya al aumentar la presin es vlido y generalizable para cualquier equilibrio en el que intervengan gases . Lgicamente, si la presin disminuye, el efecto es el contrario. Si el nmero de moles total de reactivos es igual al de productos (a+b =c+d) se pueden eliminar todos los volmenes en la expresin de Kc, con lo que ste no afecta al equilibrio (y por tanto, tampoco la presin). &3L>    O >+ Ejemplo: Una mezcla gaseosa constituida inicial-mente por 3,5 moles de hidrgeno y 2,5 de yodo, se calienta a 400C con lo que al alcanzar el equilibrio se obtienen 4.5 moles de HI, siendo el volumen del recipiente de reaccin de 10 litros. Calcule: a) El valor de las constantes de equilibrio Kc y Kp; b) La concentracin de los compuestos si el volumen se reduce a la mitad manteniendo constante la temperatura a 400C. ff+   fu@(    y a) Equilibrio: H2 (g) + I2 (g) 2 HI (g) Moles inic.: 3,5 2,5 0 Moles reac: 2,25 2,25 (4,5) Moles equil. 1,25 0,25 4,5 conc. eq(mol/l) 0,125 0,025 0,45 [HI]2 0,452 M2 Kc =     =          = 64,8 [H2] [I2] 0,125 M 0,025 M KP = Kc (RT)0 = 64,8Ugp<2p<f      3   3a  '         @-Ejemplo (cont.): b) La concentracin de los compuestos si el volumen se reduce a la mitad manteniendo constante la temperatura a 400C.T f  f ffu  b) En este caso el volumen no influye en el equilibrio, pues al haber el mismo n de moles de reactivos y productos, se eliminan todas las  V en la expresin de KC. Por tanto, las concentraciones de reactivos y productos, simplemente se duplican: [H2] = 1,25 mol/5 L = 0,250 M [I2] = 0,25 mol/5 L = 0, 050 M [HI] =4,5 mol/ 5 L = 0,90 M Se puede comprobar que: [HI]2 (0,90 M)2 Kc =     =         = 64,8 [H2] [I2] 0,250 M 0,050 Moqp<2fr/ U  .  3    3#Cambio en la temperatura.  9Se observa que, al aumentar T el sistema se desplaza hacia donde se consuma calor, es decir, hacia la izquierda en las reacciones exotrmicas y hacia la derecha en las endotrmicas. Si disminuye T el sistema se desplaza hacia donde se desprenda calor (derecha en las exotrmicas e izquierda en las endotrmicas).:: : 2"&Ejemplo: Hacia dnde se desplazar el equilibrio al: a) disminuir la presin? b) aumentar la temperatura? H2O(g) + C(s) CO(g) + H2(g) (DH > 0) f/ff  (    Hay que tener en cuenta que las concentraciones de los slidos ya estn incluidas en la Kc por ser constantes. [CO] [H2] Kc =       [H2O] a) Al p el equilibrio (donde ms moles de gases hay: 1 de CO + 1 de H2 frente a 1 slo de H2O) b) Al T el equilibrio tambin se desplaza hacia donde se consume calor por ser la reaccin endotrmica. o?p<2Y  fAfh&X  # *Principio de Le Chatelier&     Un cambio o perturbacin en cualquiera de las variables que determinan el estado de equilibrio qumico produce un desplazamiento del equilibrio en el sentido de contrarrestar o minimizar el efecto causado por la perturbacin .   7'Variaciones en el equilibrio  D [reactivos] > 0 D [reactivos] < 0 D [productos] > 0 D [productos] < 0 D T > 0 (exotrmicas) D T > 0 (endotrmicas) D T < 0 (exotrmicas) D T < 0 (endotrmicas) D p > 0 Hacia donde menos n moles de gases D p < 0 Hacia donde ms n moles de gases"lk l j>%Importancia en procesos industriales. & Es muy importante en la industria el saber qu condiciones favorecen el desplaza-miento de un equilibrio hacia la formacin de un producto, pues se conseguir un mayor rendimiento, en dicho proceso. 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Hfgֳgֳ ?"& v f r:Haga clic para modificar el estilo de subttulo del patrn;;   " Tfgֳgֳ ?"P  p f `*"     # T8fgֳgֳ ?"Ff  f T*   $ T\gֳgֳ ?"e f T*  0%T  :  "r ;  Bvd @?g7 <  3 rlgֳgֳvd @?g < 2  l =  <v @?g >  # l gֳgֳv @?7p < 2   ?   BXCDElFtv2 @?W4WO;,n2 Fm -<)8oETO'WWu78@L 6  @   BXCDElFtv2 @?W4WO;,m2 Dl -<)8oETO'WWu78@\ 6  A   BXCDElFtv2 @?W4WO;,m2 Dl -<)8oETO'WWu78@] 6 B   BXCDElFtv2 @?W4WO;,n2 El -<)8oETO'WWu78@\ 6 C   BXCDElFtv2 @?W4WO;,n2 El -<)8oETO'WWu78@]6b D   2B CDEDFLv2 @?4Bn-oT'u#$@-\6 E   BXCDElFtv2 @?W4WO;,m2 Dl -<)8oETO'WWu78@> 6  F   BZC?DElFtv2 @?YWzPt;t,z&2 >%@ LRU-U<Ou*B9'F IYW-78@g8 r G  Bvd @?7w H  3 rgֳgֳvd @?w < 2  l I  <v @?w J  # lgֳgֳv @?7w < 2   K   BXCDElFtv2 @?W4WO;,n2 El -<)8oETO'WWu78@6w L   BXCDElFtv2 @?W4WO;,m2 Dl -<)8oETO'WWu78@6w M   BXCDElFtv2 @?W4WO;,m2 Dl -<)8oETO'WWu78@6w N   BXCDElFtv2 @?W4WO;,n2 El -<)8oETO'WWu78@6x O   BXCDElFtv2 @?W4WO;,n2 Fm -<)8oETO'WWu78@6y" P   B]CDE$F,v2 @? Y4\+;oHTR'YYu@R8 Q   BXCDElFtv2 @?W4WO;,n2 El -<)8oETO'WWu78@6Y R   BZC>DElFtv2 @?YWzPt;t,z&2 =$? KQT-T<Nu*B9'F IYW-78@8;J S   BC&DE8F@v2 @?2z % ' 39<-<<6n @z  T   BXCDElFtv2 @?W4WO;,n2 El -<)8oETO'WWu78@6 l U  <v @?~B V  N1?~B W  N1?T Jr X  "Jr~ Y  Nv @?rN J Z  JN J [  JJN J \  Jl ]  <vd @?Mvf ^  6v @?M~ _ NGU v @?J ` TGU vd @?~ a  Nv @?W2 b  3 rdgֳgֳvd @? < 2  2 c  # l"gֳgֳv @?/9 < 2  2 d  3 r%gֳgֳvd @?p\ < 2   N zA9 e  zA92 f  # CENHZQvd @? `T`T`T`TXz2 g  3 CE$GHI`TQv @? `T`T`T`T`T`T`T`T`T`T;]x" h  HG/*v2 @? i   BCDEFvd @?@@oUH=4+% |pdXLA6- # )3?IOHC@<#:.989C<J?QCWI[N]U_\`fbpd|gjot{@zW j   BCDEFvd @?@@o"U$H&=)4.+2%8>EM V `lx )3?IOHC@<:99<?CINU}\{fzpx|uqmhaYOE9/% @[92 k  3 r+gֳgֳvd @?=Auu < 2  8Z * .  9# " 2 / C x.gֳgֳvd @?* .  < 2  2 0 3 rh2gֳgֳv @?u  u < 2  2 1 C x 6gֳgֳvd @? S 7 < 2  0R < # lZx:1?"Td @ 0 0 >  N  6޽h? ?/ f g  33Պ3ff3 0 y0(    Zb1 ?P   e V*    Z0b1 ?   e X*  d  c $ ?  e]  Z b1 ? @ e kHaga clic para modificar el estilo de texto del patrn Segundo nivel Tercer nivel Cuarto nivel Quinto nivel7   l    `!e1 ?`P  e V*     `|%e1 ?`  e X*  H  0޽h ? ̙3380___PPT10.2 sh 0l(  l l 0f P   f R*    l 0̾f    f T*    l 6f `P  f R*    l 6(f `  f T*   H l 0޽h ? ̙3380___PPT10.2 {^ 0N0 P@D(  M8;  l  C F f$     C G! & v<$ 0  N  6޽h? ? 33Պ3ff34,___PPT10 .$>  0 ptt(  tr t S  e    t S z!\ <$ 0  0X& ! I q H t 0޽h ? 33Պ3ff3;;___PPT10;.+/D`;' = @B D;' = @BA?%,( < +O%,( < +DN' =%(D' =%(D' =A@BBBB0B%(D' =1:Bvisible*o3>+B#style.visibility<*t%%(D' =+4 8?dCB0-#ppt_w/2BCB#ppt_xB*Y3>B ppt_x<*t%D' =+4 8?\CB#ppt_yBCB#ppt_yB*Y3>B ppt_y<*t%D' =A@BBBB0B%(D' =1:Bvisible*o3>+B#style.visibility<*t%i%(D' =+4 8?dCB0-#ppt_w/2BCB#ppt_xB*Y3>B ppt_x<*t%iD' =+4 8?\CB#ppt_yBCB#ppt_yB*Y3>B ppt_y<*t%iD{' =%(D#' =%(D' =A@BBBB0B%(D' =1:Bvisible*o3>+B#style.visibility<*ti%(D' =+4 8?dCB0-#ppt_w/2BCB#ppt_xB*Y3>B ppt_x<*tiD' =+4 8?\CB#ppt_yBCB#ppt_yB*Y3>B ppt_y<*tiDN' =%(D' =%(D' =A@BBBB0B%(D' =1:Bvisible*o3>+B#style.visibility<*t%(D' =+4 8?dCB0-#ppt_w/2BCB#ppt_xB*Y3>B ppt_x<*tD' =+4 8?\CB#ppt_yBCB#ppt_yB*Y3>B ppt_y<*tD' =A@BBBB0B%(D' =1:Bvisible*o3>+B#style.visibility<*t%(D' =+4 8?dCB0-#ppt_w/2BCB#ppt_xB*Y3>B ppt_x<*tD' =+4 8?\CB#ppt_yBCB#ppt_yB*Y3>B ppt_y<*tDN' =%(D' =%(D' =A@BBBB0B%(D' =1:Bvisible*o3>+B#style.visibility<*t%(D' =+4 8?dCB0-#ppt_w/2BCB#ppt_xB*Y3>B ppt_x<*tD' =+4 8?\CB#ppt_yBCB#ppt_yB*Y3>B ppt_y<*tD' =A@BBBB0B%(D' =1:Bvisible*o3>+B#style.visibility<*t %(D' =+4 8?dCB0-#ppt_w/2BCB#ppt_xB*Y3>B ppt_x<*t D' =+4 8?\CB#ppt_yBCB#ppt_yB*Y3>B ppt_y<*t D{' =%(D#' =%(D' =A@BBBB0B%(D' =1:Bvisible*o3>+B#style.visibility<*t $%(D' =+4 8?dCB0-#ppt_w/2BCB#ppt_xB*Y3>B ppt_x<*t $D' =+4 8?\CB#ppt_yBCB#ppt_yB*Y3>B ppt_y<*t $D' =%(Do' =%(D' =A@BBBB0B%(D' =1:Bvisible*o3>+B#style.visibility<*t$b%(D' =+4 8?dCB0-#ppt_w/2BCB#ppt_xB*Y3>B ppt_x<*t$bD' =+4 8?\CB#ppt_yBCB#ppt_yB*Y3>B ppt_y<*t$bD' =A@BBBB0B%(D' =1:Bvisible*o3>+B#style.visibility<*tb%(D' =+4 8?dCB0-#ppt_w/2BCB#ppt_xB*Y3>B ppt_x<*tbD' =+4 8?\CB#ppt_yBCB#ppt_yB*Y3>B ppt_y<*tbD' =A@BBBB0B%(D' =1:Bvisible*o3>+B#style.visibility<*t%(D' =+4 8?dCB0-#ppt_w/2BCB#ppt_xB*Y3>B ppt_x<*tD' =+4 8?\CB#ppt_yBCB#ppt_yB*Y3>B ppt_y<*tD' =A@BBBB0B%(D' =1:Bvisible*o3>+B#style.visibility<*t%(D' =+4 8?dCB0-#ppt_w/2BCB#ppt_xB*Y3>B ppt_x<*tD' =+4 8?\CB#ppt_yBCB#ppt_yB*Y3>B ppt_y<*tD' =A@BBBB0B%(D' =1:Bvisible*o3>+B#style.visibility<*t%(D' =+4 8?dCB0-#ppt_w/2BCB#ppt_xB*Y3>B ppt_x<*tD' =+4 8?\CB#ppt_yBCB#ppt_yB*Y3>B ppt_y<*tD{' =%(D#' =%(D' =A@BBBB0B%(D' =1:Bvisible*o3>+B#style.visibility<*t"%(D' =+4 8?dCB0-#ppt_w/2BCB#ppt_xB*Y3>B ppt_x<*t"D' =+4 8?\CB#ppt_yBCB#ppt_yB*Y3>B ppt_y<*t"+8+0+t0 +^  0N0  P(   X l  C , e     c $h !ve<$ 0  B  s *޽h ? 33___4,___PPT10 .w  0 .( h l  C  e`     C ZABEquilibrio molculas (Anaya 195)GpH  0޽h ? 33Պ3ff3y___PPT10Y+D=' 3 = @B +  0 C ; 8  ( 4) l  C  e`    8 l' #l'\   S ̙"`-'k N ml  " ml 6B      N ml  ! ml 6B     <B  # xT   # Z2K   @AB CDEFjJ:tb @ 3"`F <B  # jJF  lT @  # 2  @AB CDEFjJ:tb @ "`F@ <B  # jJF@ @ lT  # 2   @AB C DEFfjJ FZ @ "`F<B  # fjJF  S h"` 6 pEquilibrio qumico.he    s *d{"`ml  uConcentraciones (mol/l).hd@    S "`   l Tiempo (s)& d     S "`{Z f[HI]&df    S "`   [I2]@`h`    S h"`= _  [H2]Lhaia  <B  #   H  0޽h ? 33Պ3ff3y___PPT10Y+D=' & = @B +  0 pb(  r  S ( u     p0e0eA!Equilibrio>6 H  0޽h ? 33Պ3ff3___PPT10e.+D=' & = @B +  0N0  (  Xr X S  9     X S l!<$  0    # l1? !  8A ?3?"? 8 $D  0H X 0޽h ? 33Պ3ff3___PPT10.+D' = @B DC' = @BA?%,( < +O%,( < +D{' =%(D#' =%(D' =A@BBBB0B%(D' =1:Bvisible*o3>+B#style.visibility<*XU%(D' =+4 8?\CB#ppt_xBCB#ppt_xB*Y3>B ppt_x<*XUD' =+4 8?dCB1+#ppt_h/2BCB#ppt_yB*Y3>B ppt_y<*XUDn' =%(D' =%(D' =4@BBBB%(D' =1:Bvisible*o3>+B#style.visibility<*%(D' =+4 8?\CB#ppt_xBCB#ppt_xB*Y3>B ppt_x<*D' =+4 8?dCB1+#ppt_h/2BCB#ppt_yB*Y3>B ppt_y<*D{' =%(D#' =%(D' =A@BBBB0B%(D' =1:Bvisible*o3>+B#style.visibility<*XX~%(D' =+4 8?\CB#ppt_xBCB#ppt_xB*Y3>B ppt_x<*XX~D' =+4 8?dCB1+#ppt_h/2BCB#ppt_yB*Y3>B ppt_y<*XX~D{' =%(D#' =%(D' =A@BBBB0B%(D' =1:Bvisible*o3>+B#style.visibility<*X~%(D' =+4 8?\CB#ppt_xBCB#ppt_xB*Y3>B ppt_x<*X~D' =+4 8?dCB1+#ppt_h/2BCB#ppt_yB*Y3>B ppt_y<*X~D{' =%(D#' =%(D' =A@BBBB0B%(D' =1:Bvisible*o3>+B#style.visibility<*Xm%(D' =+4 8?\CB#ppt_xBCB#ppt_xB*Y3>B ppt_x<*XmD' =+4 8?dCB1+#ppt_h/2BCB#ppt_yB*Y3>B ppt_y<*Xm+8+0+X0 +  0N0  (  r  S 8 9      S  !=<$  0    # l1?M "  8A ?3?"?8 $D  0H  0޽h ? 33Պ3ff3___PPT10e.+D'  = @B D' = @BA?%,( < +O%,( < +D{' =%(D#' =%(D' =A@BBBB0B%(D' =1:Bvisible*o3>+B#style.visibility<*1%(D' =+4 8?\CB#ppt_xBCB#ppt_xB*Y3>B ppt_x<*1D' =+4 8?dCB1+#ppt_h/2BCB#ppt_yB*Y3>B ppt_y<*1Dn' =%(D' =%(D' =4@BBBB%(D' =1:Bvisible*o3>+B#style.visibility<*%(D' =+4 8?\CB#ppt_xBCB#ppt_xB*Y3>B ppt_x<*D' =+4 8?dCB1+#ppt_h/2BCB#ppt_yB*Y3>B ppt_y<*D{' =%(D#' =%(D' =A@BBBB0B%(D' =1:Bvisible*o3>+B#style.visibility<*4%(D' =+4 8?\CB#ppt_xBCB#ppt_xB*Y3>B ppt_x<*4D' =+4 8?dCB1+#ppt_h/2BCB#ppt_yB*Y3>B ppt_y<*4D{' =%(D#' =%(D' =A@BBBB0B%(D' =1:Bvisible*o3>+B#style.visibility<*%(D' =+4 8?\CB#ppt_xBCB#ppt_xB*Y3>B ppt_x<*D' =+4 8?dCB1+#ppt_h/2BCB#ppt_yB*Y3>B ppt_y<*+8+0+0 +d  0 ]]HJb](    c $    \ V J #"."OPOOOOV<$D 0 ` p # l(a`1?,z0___PPT10:___PPT9 W280,66(" "# o # l*1?,z0___PPT10:___PPT9 W0,3636(" "# n # ld+1?z0___PPT10:___PPT9 W0,3436(" "# m # lx/1? z0___PPT10:___PPT9 W0,0376(" "# l # l@01?  z0___PPT10:___PPT9 V0,256(" "# k # l91?s z0___PPT10:___PPT9 V0,406(" "# j # l?1? sz0___PPT10:___PPT9 V0,156(" "# i 3 r+1? z0___PPT10:___PPT9 iExp 54(" "#   h # l F1?,Lz0___PPT10:___PPT9 k280,56(" "#   g # lF1?L,z0___PPT10:___PPT9 k0,5686(" "#   f # lpL1?Lz0___PPT10:___PPT9 k0,0666(" "#   e # l8R1? Lz0___PPT10:___PPT9 k0,1326(" "#   d # l+B#style.visibility<*J%(D' =+4 8?dCB0-#ppt_w/2BCB#ppt_xB*Y3>B ppt_x<*JD' =+4 8?\CB#ppt_yBCB#ppt_yB*Y3>B ppt_y<*J+ou  0N0 ccJnc( ;IN L L S #!5Z<$ 0  >a /e   #"."U      /e   N # l 1 ?e z0___PPT10:___PPT9 m280,66(" "# @` O # l1 ? z0___PPT10:___PPT9 m0,3636(" "# @` P # lR1 ?b z0___PPT10:___PPT9 m0,3436(" "# @` Q # lT]1 ? b z0___PPT10:___PPT9 m0,0376(" "# @` R # lX1 ?  z0___PPT10:___PPT9 l0,256(" "# @` S # lS1 ?J z0___PPT10:___PPT9 l0,406(" "# @` T # lh1 ?J z0___PPT10:___PPT9 l0,156(" "# @` U 3 r~1 ? z0___PPT10:___PPT9 Exp 54(" "#   @` V # l01 ?ez0___PPT10:___PPT9 280,56(" "#   @` W # l1 ?z0___PPT10:___PPT9 0,5686(" "#   @` X # l81 ?bz0___PPT10:___PPT9 0,0666(" "#   @` Y # lЕ1 ? bz0___PPT10:___PPT9 0,1326(" "#   @` Z # l1 ?  z0___PPT10:___PPT9 0,706(" "#   @` [ # l1 ?J z0___PPT10:___PPT9 ~ 6(" "#   @` \ # l1 ?Jz0___PPT10:___PPT9 ~ 6(" "#   @` ] 3 r 1 ?z0___PPT10:___PPT9 Exp 44(" "#   @` ^ # l1 ?ez0___PPT10:___PPT9 280,06(" "#   @` _ # l81 ?z0___PPT10:___PPT9 0,1436(" "#   @` ` # lh1 ?bz0___PPT10:___PPT9 0,0266(" "#   @` a # l1 ? bz0___PPT10:___PPT9 0,0536(" "#   @` b # l1 ?  z0___PPT10:___PPT9 0,206(" "#   @` c # l1 ?J z0___PPT10:___PPT9 ~ 6(" "#   @` d # l01 ?Jz0___PPT10:___PPT9 ~ 6(" "#   @` e 3 r1 ?z0___PPT10:___PPT9 Exp 34(" "#   @` f # l61 ?ez0___PPT10:___PPT9 280,76(" "#   @` g # lA1 ?z0___PPT10:___PPT9 0,1356(" "#   @` h # l;1 ?bz0___PPT10:___PPT9 0,3326(" "#   @` i # l,=1 ? bz0___PPT10:___PPT9 0,0146(" "#   @` j # l`1 ?  z0___PPT10:___PPT9 ~ 6(" "#   @` k # ll1 ?J z0___PPT10:___PPT9 0,406(" "#   @` l # lu1 ?Jz0___PPT10:___PPT9 0,156(" "#   @` m 3 rDy1 ?z0___PPT10:___PPT9 Exp 24(" "#   @` n # lx1 ?ez0___PPT10:___PPT9 279,26(" "#   @` o # l[1 ?z0___PPT10:___PPT9 0,1706(" "#   @` p # l\1 ?bz0___PPT10:___PPT9 0,1556(" "#   @` q # l01 ? bz0___PPT10:___PPT9 0,0306(" "#   @` r # lT1 ?  z0___PPT10:___PPT9 ~ 6(" "#   @` s # l1 ?J z0___PPT10:___PPT9 0,206(" "#   @` t # l01 ?Jz0___PPT10:___PPT9 0,206(" "#   @` u 3 r1 ?z0___PPT10:___PPT9 Exp 14(" "#   @` v # lD1 ?ez0___PPT10:___PPT9 KcF(" "*#   @` w # lHf1 ?z0___PPT10:___PPT9 [SO3]N(" "*"#   @` x # lPf1 ?bz0___PPT10:___PPT9 [O2]N(" "*"#   @` y # lf1 ? bz0___PPT10:___PPT9 [SO2]N(" "*"#   @` z # lL 1 ?  z0___PPT10:___PPT9 [SO3]N(" "*"#   @` { # l 1 ?J z0___PPT10:___PPT9 [O2]N(" "*"#   @` | # l1 ?Jz0___PPT10:___PPT9 [SO2]N(" "*"#   @` } 3 r8&1 ? V    @`, ~  :̙@q=d @1 ?" /e V    @`  # l;̙1 ? /z0___PPT10:___PPT9 Concentr. equilibrio (mol/l)8(" &#$   @`  # l<̙1 ?/ z0___PPT10:___PPT9 Concentr. iniciales (mol/l)8(" &#$   @`  # lY̙1 ?/ V    @`~B  N1 ?/e/~B  N1 ? e ~B  N1 ?/ ~B  N1 ?e/e ~B  N1 ?e~B  N1 ?/ ~B  N1 ? / ~B  N1 ?/ ~B  N1 ?e~B  N1 ?JJ ~B  N1 ?  ~B  N1 ?bb ~B  N1 ? ~B  N1 ?e~B  N1 ?e~B  N1 ?e~B  N1 ?e  # l1? .   8A ?3?"? )G8 $D 0H L 0޽h ? 33Պ3ff3!___PPT10.+є%D' & = @B DT' = @BA?%,( < +O%,( < +D' =%(D|' =%(D$' =A@BBB B0B%(E' =4 B`BPB`B?<*%(/%,( < +D' =1:Bvisible*o3>+B#style.visibility<*L6%(D' =-o6Bbox(out)*<3<*L6D' =%(D|' =%(D$' =A@BBB B0B%(E' =4 B`BPB`B?<*%( /%,( < +D' =1:Bvisible*o3>+B#style.visibility<*L6]%(D' =-o6Bbox(out)*<3<*L6]D' =%(D' =%(DG' =4@BBB B%()))E' =4 B`BPB`B?<*%(/%,( < +D' =1:Bvisible*o3>+B#style.visibility<*%(D' =-o6Bbox(out)*<3<*D' =%(D|' =%(D$' =A@BBB B0B%(E' =4 B`BPB`B?<*%(/%,( < +D' =1:Bvisible*o3>+B#style.visibility<*L_%(D' =-o6Bbox(out)*<3<*L_+8+0+L0 +0  0 ((  ( ( c $u    s  ( S P!r Z<$  0    ( S !z; eZ<$  0  0 (0 c 0e0eA ?3 !?s"*` ?  H $  0   ( JA ?3 ??#" `?  ; 8 $D 0  ( JA  ?3 ??#" `?8 $D 0 ( JA  ?3 ??#" `?t o 8 $D  0H ( 0޽h ? 33Պ3ff3T*L*___PPT10,*.. nQ+lDL)' = @B D)' = @BA?%,( < +O%,( < +D ' =%(DT ' =%(D' =A@BBBB0B%(E5' =1B B`BPB,54*3>B ppt_c='`B@BPB<* (D' =1:Bvisible*o3>+B#style.visibility<* (%(D' =+4 8?dCB0-#ppt_w/2BCB#ppt_xB*Y3>B ppt_x<* (D' =+4 8?\CB#ppt_yBCB#ppt_yB*Y3>B ppt_y<* (D' =A@BBBB0B%(E5' =1B BPB`B,54*3>B ppt_c='`B@BPB<*(E' =4 BPB`B`B?<*%( /%,( < +D' =1:Bvisible*o3>+B#style.visibility<*(%(D' =+4 8?dCB0-#ppt_w/2BCB#ppt_xB*Y3>B ppt_x<*(D' =+4 8?\CB#ppt_yBCB#ppt_yB*Y3>B ppt_y<*(D~ ' =%(D& ' =%(D' =A@BBBB0B%(E5' =1B B`BPB,54*3>B ppt_c='`B@BPB<* (D' =1:Bvisible*o3>+B#style.visibility<* (%(D' =+4 8?dCB0-#ppt_w/2BCB#ppt_xB*Y3>B ppt_x<* (D' =+4 8?\CB#ppt_yBCB#ppt_yB*Y3>B ppt_y<* (D' =4@BBBB%(D' =1:Bvisible*o3>+B#style.visibility<* (%(D' =+4 8?dCB0-#ppt_w/2BCB#ppt_xB*Y3>B ppt_x<* (D' =+4 8?\CB#ppt_yBCB#ppt_yB*Y3>B ppt_y<* (D~ ' =%(D& ' =%(D' =A@BBBB0B%(E5' =1B B`BPB,54*3>B ppt_c='`B@BPB<* (D' =1:Bvisible*o3>+B#style.visibility<* (%(D' =+4 8?dCB0-#ppt_w/2BCB#ppt_xB*Y3>B ppt_x<* (D' =+4 8?\CB#ppt_yBCB#ppt_yB*Y3>B ppt_y<* (D' =4@BBBB%(D' =1:Bvisible*o3>+B#style.visibility<* (%(D' =+4 8?dCB0-#ppt_w/2BCB#ppt_xB*Y3>B ppt_x<* (D' =+4 8?\CB#ppt_yBCB#ppt_yB*Y3>B ppt_y<* (D~ ' =%(D& ' =%(D' =A@BBBB0B%(E5' =1B B`BPB,54*3>B ppt_c='`B@BPB<* (D' =1:Bvisible*o3>+B#style.visibility<* (%(D' =+4 8?dCB0-#ppt_w/2BCB#ppt_xB*Y3>B ppt_x<* (D' =+4 8?\CB#ppt_yBCB#ppt_yB*Y3>B ppt_y<* (D' =4@BBBB%(D' =1:Bvisible*o3>+B#style.visibility<*(%(D' =+4 8?dCB0-#ppt_w/2BCB#ppt_xB*Y3>B ppt_x<*(D' =+4 8?\CB#ppt_yBCB#ppt_yB*Y3>B ppt_y<*(++0+ (0 ++0+ (0 ++0+(0 +'  0 .B P(  l  C Ѝ`   ` T  S ̙"f 6 |  A#  d ,$D  0T t  # ~   @AB CDEFjJ:tb @ 3"`tBB  3 jJ  rT %   # ~   @AB C DEFfjJ FZ @ "`% O <B  # fjJ=%  % ,N p |  @ p | N p  ? p NB  S Dp p NB  S Dp   c $`l|  htiempo&d   - c $$`- 6 g KC H" 100X dldl   0 s *ܠ06   k concentracin" `    0  ># ? p ,$D  0&T  U) # 3 T t% -  #  v(HB  C Dt% t HB  C Dt -   S t $(U) htiempo&d  I@ 0y 4 <0y 4T t  &# 3y  ' @AB CDEFjJ:tb @ 3"`tBB ( 3 jJ  rT %   )# 3sg 4 * @AB C DEFfjJ FZ @ "`% O <B + # fjJ=%  %  , c $,:Rh k KC > 105X dldl   1 B1"`0! k concentracin" `    n ) =#  bL,$D  0T t   #    ! @AB CDEFjJ:tb @ 3"`tBB " 3 jJ  rT %   ##  c $ @AB C DEFfjJ FZ @ "`% O <B % # fjJ=%  %  . c $p.T 5 KP   KC < 10-2X dldl    / s */n%  k concentracin" `   &T  T') 3#  )T t% -  4#  &v(HB 5 C Dt% t HB 6 C Dt -  7 S 7##(T') htiempo&d  H  0޽h ? 33Պ3ff3___PPT10+URDh' = @B D#' = @BA?%,( < +O%,( < +Dn' =%(D' =%(D' =4@BBBB%(D' =1:Bvisible*o3>+B#style.visibility<*>%(D' =+4 8?\CB#ppt_xBCB#ppt_xB*Y3>B ppt_x<*>D' =+4 8?dCB1+#ppt_h/2BCB#ppt_yB*Y3>B ppt_y<*>Dn' =%(D' =%(D' =4@BBBB%(D' =1:Bvisible*o3>+B#style.visibility<*A%(D' =+4 8?\CB#ppt_xBCB#ppt_xB*Y3>B ppt_x<*AD' =+4 8?dCB1+#ppt_h/2BCB#ppt_yB*Y3>B ppt_y<*ADn' =%(D' =%(D' =4@BBBB%(D' =1:Bvisible*o3>+B#style.visibility<*=%(D' =+4 8?\CB#ppt_xBCB#ppt_xB*Y3>B ppt_x<*=D' =+4 8?dCB1+#ppt_h/2BCB#ppt_yB*Y3>B ppt_y<*=+p  0N0 ( Dp0$ z \ C  p@  ` e \ C !m<$  0   \ T1?x P,$D 0H  0޽h ? 33Պ3ff3xp___PPT10P.+*D'  = @B D' = @BA?%,( < +O%,( < +D' =%(D' =%(DN' =A@BB BB0B%(D' =1:Bvisible*o3>+B#style.visibility<*\0%(D' =-}6B!slide(fromLeft)*<3<*\0D' =%(D' =%(DN' =A@BB BB0B%(D' =1:Bvisible*o3>+B#style.visibility<*\0X%(D' =-}6B!slide(fromLeft)*<3<*\0XD' =%(D' =%(DN' =A@BB BB0B%(D' =1:Bvisible*o3>+B#style.visibility<*\X%(D' =-}6B!slide(fromLeft)*<3<*\XD' =%(D' =%(DN' =A@BB BB0B%(D' =1:Bvisible*o3>+B#style.visibility<*\%(D' =-}6B!slide(fromLeft)*<3<*\D' =%(D' =%(DN' =A@BB BB0B%(D' =1:Bvisible*o3>+B#style.visibility<*\%(D' =-}6B!slide(fromLeft)*<3<*\D' =%(Dl' =%(DN' =A@BB BB0B%(D' =1:Bvisible*o3>+B#style.visibility<*\\%(D' =-}6B!slide(fromLeft)*<3<*\\D' =4@BBBB%(D' =1:Bvisible*o3>+B#style.visibility<*\%(D' =+4 8?dCB0-#ppt_w/2BCB#ppt_xB*Y3>B ppt_x<*\D' =+4 8?\CB#ppt_yBCB#ppt_yB*Y3>B ppt_y<*\+8+0+\0 +  0N0 8|(  8 8 S p` '  ` e4 8 s `gֳgֳ ?!#" 0ej<$ 0 ` "8*V 8 s ,A  ??#" `?  8 $D 0  8 s ,A s??#" `? 8 s$D 0  8 s ,A  ??#" `? 8 $D 0p 8  fXa̙1?`,$D 0 6Moles equil. 0,0014 0,013 0,0137732  +  H 8 0޽h ? 33Պ3ff3{___PPT10[.+SڞD' 3 = @B D~' = @BA?%,( < +O%,( < +D4' =%(D' =%(D' =A@BBB B0B%()))D' =1:Bvisible*o3>+B#style.visibility<*88%(D' =-6B'blinds(horizontal)*<3<*88D4' =%(D' =%(D' =A@BBB B0B%()))D' =1:Bvisible*o3>+B#style.visibility<*88j%(D' =-6B'blinds(horizontal)*<3<*88jD4' =%(D' =%(D' =A@BBB B0B%()))D' =1:Bvisible*o3>+B#style.visibility<*8j%(D' =-6B'blinds(horizontal)*<3<*8jD' =%(D' =%(DG' =4@BBB B%(D' =1:Bvisible*o3>+B#style.visibility<*8%(D' =-6B'blinds(horizontal)*<3<*8D' =%(D' =%(DG' =4@BBB B%(D' =1:Bvisible*o3>+B#style.visibility<* 8%(D' =-6B'blinds(horizontal)*<3<* 8D' =%(D' =%(DG' =4@BBB B%(D' =1:Bvisible*o3>+B#style.visibility<* 8%(D' =-6B'blinds(horizontal)*<3<* 8D' =%(D' =%(DT' =A@BBB B0B%(D' =1:Bvisible*o3>+B#style.visibility<*8%(D' =-6B'blinds(horizontal)*<3<*8+p+0+80 ++0+80 +'  0N0 0( (  `r ` S h e`    ` c $ !e<$  0  $p.Zb  # l1?  8A  ?3?"?v  8 $D  0H ` 0޽h ? 33Պ3ff3  ___PPT10_ .+ D ' $= @B D ' = @BA?%,( < +O%,( < +D{' =%(D#' =%(D' =A@BBBB0B%(D' =1:Bvisible*o3>+B#style.visibility<*`%(D' =+4 8?\CB#ppt_xBCB#ppt_xB*Y3>B ppt_x<*`D' =+4 8?dCB1+#ppt_h/2BCB#ppt_yB*Y3>B ppt_y<*`Dn' =%(D' =%(D' =4@BBBB%(D' =1:Bvisible*o3>+B#style.visibility<*%(D' =+4 8?\CB#ppt_xBCB#ppt_xB*Y3>B ppt_x<*D' =+4 8?dCB1+#ppt_h/2BCB#ppt_yB*Y3>B ppt_y<*+8+0+`0 +  0N0 0P(  dr d S p,     d S p-!jW<$ 0  H d 0޽h ? 33Պ3ff3___PPT10.+$MDV' 3 = @B D' = @BA?%,( < +O%,( < +D' =%(D' =%(DX' =A@BBB B0B%(D' =1:Bvisible*o3>+B#style.visibility<*dA%(D' =-6B+checkerboard(across)*<3<*dAD' =%(D' =%(DX' =A@BBB B0B%(D' =1:Bvisible*o3>+B#style.visibility<*dA%(D' =-6B+checkerboard(across)*<3<*dAD' =%(D' =%(DX' =A@BBB B0B%(D' =1:Bvisible*o3>+B#style.visibility<*d%(D' =-6B+checkerboard(across)*<3<*dD' =%(D' =%(DX' =A@BBB B0B%(D' =1:Bvisible*o3>+B#style.visibility<*d%(D' =-6B+checkerboard(across)*<3<*dD' =%(D' =%(DX' =A@BBB B0B%(D' =1:Bvisible*o3>+B#style.visibility<*dN%(D' =-6B+checkerboard(across)*<3<*dN+8+0+d0 +   0N0 @( `  l h C 9 e`    h C :!{<$ 0    # l1? #  8A ?3?"? h 8 $D 0H  0޽h ? 33Պ3ff3}___PPT10].+IRD' 3 = @B D' = @BA?%,( < +O%,( < +D' =%(D' =%(DU' =A@BB4BB0B%()))D' =1:Bvisible*o3>+B#style.visibility<*hk%(D' =0l9 BBzCzCBB*<3<*hk%())?D' =.7 BBBBBM -0.46736 0.92887 C -0.37517 0.88508 -0.02552 0.75279 0.0908 0.66613 C 0.20747 0.57948 0.21649 0.50394 0.23177 0.40825 C 0.24705 0.31256 0.22118 0.15964 0.18264 0.09152 C 0.1441 0.02341 0.03802 0.0 0.0 0.0 *3>*B ppt_xB ppt_y=B0B<*hk%())?D' =-g6B fade*<3<*hkD' =%(D' =%(DU' =A@BB4BB0B%()))D' =1:Bvisible*o3>+B#style.visibility<*hl%(D' =0l9 BBzCzCBB*<3<*hl%())?D' =.7 BBBBBM -0.46736 0.92887 C -0.37517 0.88508 -0.02552 0.75279 0.0908 0.66613 C 0.20747 0.57948 0.21649 0.50394 0.23177 0.40825 C 0.24705 0.31256 0.22118 0.15964 0.18264 0.09152 C 0.1441 0.02341 0.03802 0.0 0.0 0.0 *3>*B ppt_xB ppt_y=B0B<*hl%())?D' =-g6B fade*<3<*hlD' =%(Dp' =%(D' =4@BB4BB%(D' =1:Bvisible*o3>+B#style.visibility<*%(D' =0l9 BBzCzCBB*<3<*%())?D' =.7 BBBBBM -0.46736 0.92887 C -0.37517 0.88508 -0.02552 0.75279 0.0908 0.66613 C 0.20747 0.57948 0.21649 0.50394 0.23177 0.40825 C 0.24705 0.31256 0.22118 0.15964 0.18264 0.09152 C 0.1441 0.02341 0.03802 0.0 0.0 0.0 *3>*B ppt_xB ppt_y=B0B<*%())?D' =-g6B fade*<3<*D' =%(D' =%(DU' =A@BB4BB0B%()))D' =1:Bvisible*o3>+B#style.visibility<*h<%(D' =0l9 BBzCzCBB*<3<*h<%())?D' =.7 BBBBBM -0.46736 0.92887 C -0.37517 0.88508 -0.02552 0.75279 0.0908 0.66613 C 0.20747 0.57948 0.21649 0.50394 0.23177 0.40825 C 0.24705 0.31256 0.22118 0.15964 0.18264 0.09152 C 0.1441 0.02341 0.03802 0.0 0.0 0.0 *3>*B ppt_xB ppt_y=B0B<*h<%())?D' =-g6B fade*<3<*h<+8+0+h0 +6  0N0 <4`( C> pz p C X  y    p C !%<$ 0  (<*V p T1? f,$D 0l  *   p  ,$D 0R p Z1? 0 G * R  p  `1?T  H p 0޽h ? 33Պ3ff3o1g1___PPT10G1.+ D0' 3 = @B D0' = @BA?%,( < +O%,( < +D' =%(D' =%(DU' =A@BB4BB0B%()))D' =1:Bvisible*o3>+B#style.visibility<*p"%(D' =0l9 BBzCzCBB*<3<*p"%())?D' =.7 BBBBBM -0.46736 0.92887 C -0.37517 0.88508 -0.02552 0.75279 0.0908 0.66613 C 0.20747 0.57948 0.21649 0.50394 0.23177 0.40825 C 0.24705 0.31256 0.22118 0.15964 0.18264 0.09152 C 0.1441 0.02341 0.03802 0.0 0.0 0.0 *3>*B ppt_xB ppt_y=B0B<*p"%())?D' =-g6B fade*<3<*p"D' =%(D' =%(DU' =A@BB4BB0B%()))D' =1:Bvisible*o3>+B#style.visibility<*p"R%(D' =0l9 BBzCzCBB*<3<*p"R%())?D' =.7 BBBBBM -0.46736 0.92887 C -0.37517 0.88508 -0.02552 0.75279 0.0908 0.66613 C 0.20747 0.57948 0.21649 0.50394 0.23177 0.40825 C 0.24705 0.31256 0.22118 0.15964 0.18264 0.09152 C 0.1441 0.02341 0.03802 0.0 0.0 0.0 *3>*B ppt_xB ppt_y=B0B<*p"R%())?D' =-g6B fade*<3<*p"RD' =%(D' =%(DU' =A@BB4BB0B%()))D' =1:Bvisible*o3>+B#style.visibility<*pRe%(D' =0l9 BBzCzCBB*<3<*pRe%())?D' =.7 BBBBBM -0.46736 0.92887 C -0.37517 0.88508 -0.02552 0.75279 0.0908 0.66613 C 0.20747 0.57948 0.21649 0.50394 0.23177 0.40825 C 0.24705 0.31256 0.22118 0.15964 0.18264 0.09152 C 0.1441 0.02341 0.03802 0.0 0.0 0.0 *3>*B ppt_xB ppt_y=B0B<*pRe%())?D' =-g6B fade*<3<*pReDU ' =%(D ' =%(DU' =A@BB4BB0B%()))D' =1:Bvisible*o3>+B#style.visibility<*pe%(D' =0l9 BBzCzCBB*<3<*pe%())?D' =.7 BBBBBM -0.46736 0.92887 C -0.37517 0.88508 -0.02552 0.75279 0.0908 0.66613 C 0.20747 0.57948 0.21649 0.50394 0.23177 0.40825 C 0.24705 0.31256 0.22118 0.15964 0.18264 0.09152 C 0.1441 0.02341 0.03802 0.0 0.0 0.0 *3>*B ppt_xB ppt_y=B0B<*pe%())?D' =-g6B fade*<3<*peDH' =4@BB4BB%()))D' =1:Bvisible*o3>+B#style.visibility<* p%(D' =0l9 BBzCzCBB*<3<* p%())?D' =.7 BBBBBM -0.46736 0.92887 C -0.37517 0.88508 -0.02552 0.75279 0.0908 0.66613 C 0.20747 0.57948 0.21649 0.50394 0.23177 0.40825 C 0.24705 0.31256 0.22118 0.15964 0.18264 0.09152 C 0.1441 0.02341 0.03802 0.0 0.0 0.0 *3>*B ppt_xB ppt_y=B0B<* p%())?D' =-g6B fade*<3<* pDU ' =%(D ' =%(DU' =A@BB4BB0B%()))D' =1:Bvisible*o3>+B#style.visibility<*p%(D' =0l9 BBzCzCBB*<3<*p%())?D' =.7 BBBBBM -0.46736 0.92887 C -0.37517 0.88508 -0.02552 0.75279 0.0908 0.66613 C 0.20747 0.57948 0.21649 0.50394 0.23177 0.40825 C 0.24705 0.31256 0.22118 0.15964 0.18264 0.09152 C 0.1441 0.02341 0.03802 0.0 0.0 0.0 *3>*B ppt_xB ppt_y=B0B<*p%())?D' =-g6B fade*<3<*pDH' =4@BB4BB%()))D' =1:Bvisible*o3>+B#style.visibility<*p%(D' =0l9 BBzCzCBB*<3<*p%())?D' =.7 BBBBBM -0.46736 0.92887 C -0.37517 0.88508 -0.02552 0.75279 0.0908 0.66613 C 0.20747 0.57948 0.21649 0.50394 0.23177 0.40825 C 0.24705 0.31256 0.22118 0.15964 0.18264 0.09152 C 0.1441 0.02341 0.03802 0.0 0.0 0.0 *3>*B ppt_xB ppt_y=B0B<*p%())?D' =-g6B fade*<3<*p+8+0+p0 +}  0 @4(  8z 8 C H!   a z 8 C $b l   sH 8 0޽h ? 33Պ3ff3y___PPT10Y+D=' 3 = @B +  0 h``(   @ S  Jl  b  @ S a!   @ T1? r7\,$D 0H  0޽h ? 33Պ3ff3___PPT10+H{D' = @B DW' = @BA?%,( < +O%,( < +D' =%(%(D' =%(D' =4@BBBB%(D' =1:Bvisible*o3>+B#style.visibility<*@%(D' =+4 8?dCB0-#ppt_w/2BCB#ppt_xB*Y3>B ppt_x<*@D' =+4 8?\CB#ppt_yBCB#ppt_yB*Y3>B ppt_y<*@+  0N0  D(   l t C $b e`  b  t C %b!a?<$ 0 b H   0޽h ? 33Պ3ff3y___PPT10Y+2I?D=' 3 = @B +S  0N0 D(  l | C  e`    | C !eZ<$  0  H  0޽h ? 33Պ3ff3/'___PPT10.+.ɷND' ߑ|= @B Db' = @BA?%,( < +O%,( < +D' =%(D+' =%(D' =A@BBBB0B%(D' =1:Bvisible*o3>+B#style.visibility<*|c%(D' =+4 8?dCB1+#ppt_w/2BCB#ppt_xB*Y3>B ppt_x<*|cD' =+4 8?dCB1+#ppt_h/2BCB#ppt_yB*Y3>B ppt_y<*|cD' =%(D+' =%(D' =A@BBBB0B%(D' =1:Bvisible*o3>+B#style.visibility<*|c%(D' =+4 8?dCB1+#ppt_w/2BCB#ppt_xB*Y3>B ppt_x<*|cD' =+4 8?dCB1+#ppt_h/2BCB#ppt_yB*Y3>B ppt_y<*|cD' =%(D+' =%(D' =A@BBBB0B%(D' =1:Bvisible*o3>+B#style.visibility<*|%(D' =+4 8?dCB1+#ppt_w/2BCB#ppt_xB*Y3>B ppt_x<*|D' =+4 8?dCB1+#ppt_h/2BCB#ppt_yB*Y3>B ppt_y<*|+8+0+|0 +  0N0  t( w xz x C  d&   Z x c $ !Gu<$D 0  "8*VH x 0޽h ? 33Պ3ff3___PPT10`.+0 -D' 3 = @B D' = @BA?%,( < +O%,( < +D' =%(D' =%(DG' =A@BBBB0B%(D' =1:Bvisible*o3>+B#style.visibility<*x/%(D' =+v4 ,0B*O3> B<*x/D' =%(D' =%(DG' =A@BBBB0B%(D' =1:Bvisible*o3>+B#style.visibility<*x/W%(D' =+v4 ,0B*O3> B<*x/WD' =%(D' =%(DG' =A@BBBB0B%(D' =1:Bvisible*o3>+B#style.visibility<*xW%(D' =+v4 ,0B*O3> B<*xWD' =%(D' =%(DG' =A@BBBB0B%(D' =1:Bvisible*o3>+B#style.visibility<*x%(D' =+v4 ,0B*O3> B<*xD' =%(D' =%(DG' =A@BBBB0B%(D' =1:Bvisible*o3>+B#style.visibility<*x.%(D' =+v4 ,0B*O3> B<*x.D' =%(D' =%(DG' =A@BBBB0B%(D' =1:Bvisible*o3>+B#style.visibility<*x.T%(D' =+v4 ,0B*O3> B<*x.T+8+0+x0 +  0N0 R(  z  C b  ]  b e  C b!o<$D 0 b H  0޽h ? 33Պ3ff3  ___PPT10b .+0 -D ' 3 = @B D ' = @BA?%,( < +O%,( < +D' =%(D' =%(DG' =A@BBBB0B%(D' =1:Bvisible*o3>+B#style.visibility<*$%(D' =+v4 ,0B*O3> B<*$D' =%(D' =%(DG' =A@BBBB0B%(D' =1:Bvisible*o3>+B#style.visibility<*$G%(D' =+v4 ,0B*O3> B<*$GD' =%(D' =%(DG' =A@BBBB0B%(D' =1:Bvisible*o3>+B#style.visibility<*Gf%(D' =+v4 ,0B*O3> B<*GfD' =%(D' =%(DG' =A@BBBB0B%(D' =1:Bvisible*o3>+B#style.visibility<*f %(D' =+v4 ,0B*O3> B<*f +8+0+0 +2  0N0 N(  l  C \b   b   C Lb![H <$ 0 b   Za31?V u ,$D   0 D(3  H  0޽h ? 33Պ3ff3___PPT10.+bDD' 3 = @B D' = @BA?%,( < +O%,( < +D' =%(D' =%(DG' =A@BBBB0B%(D' =1:Bvisible*o3>+B#style.visibility<*%(D' =+v4 ,0B*O3> B<*D' =%(D' =%(DG' =A@BBBB0B%(D' =1:Bvisible*o3>+B#style.visibility<*%(D' =+v4 ,0B*O3> B<*D' =%(D' =%(DG' =A@BBBB0B%(D' =1:Bvisible*o3>+B#style.visibility<*%(D' =+v4 ,0B*O3> B<*D' =%(D' =%(DG' =A@BBBB0B%(D' =1:Bvisible*o3>+B#style.visibility<*%(D' =+v4 ,0B*O3> B<*D' =%(D' =%(DG' =A@BBBB0B%(D' =1:Bvisible*o3>+B#style.visibility<*%(D' =+v4 ,0B*O3> B<*D' =%(D' =%(DG' =A@BBBB0B%(D' =1:Bvisible*o3>+B#style.visibility<*%(D' =+v4 ,0B*O3> B<*D' =%(D' =%(DG' =A@BBBB0B%(D' =1:Bvisible*o3>+B#style.visibility<*%(D' =+v4 ,0B*O3> B<*D=' =%(D' =%(DG' =A@BBBB0B%(D' =1:Bvisible*o3>+B#style.visibility<*%(D' =+v4 ,0B*O3> B<*D>' =A@BBBB0B%(D' =1:Bvisible*o3>+B#style.visibility<*%(D' =-m6Bbox(in)*<3<*+p+0+0 ++0+0 +e+  0N0 80( JD z  C X^ `  ^   C /^!_p<$ 0 ^ *k'/7l      ,$D 0B B ZD31? M B B ZD31? c   T1?[ ,$@   0H  0޽h ? 33Պ3ff3&&___PPT10&.+D5&' L^= @B D%' = @BA?%,( < +O%,( < +D{' =%(D#' =%(D' =A@BBBB0B%(D' =1:Bvisible*o3>+B#style.visibility<*/%(D' =+4 8?dCB0-#ppt_w/2BCB#ppt_xB*Y3>B ppt_x<*/D' =+4 8?\CB#ppt_yBCB#ppt_yB*Y3>B ppt_y<*/D{' =%(D#' =%(D' =A@BBBB0B%(D' =1:Bvisible*o3>+B#style.visibility<*/R%(D' =+4 8?dCB0-#ppt_w/2BCB#ppt_xB*Y3>B ppt_x<*/RD' =+4 8?\CB#ppt_yBCB#ppt_yB*Y3>B ppt_y<*/RD{' =%(D#' =%(D' =A@BBBB0B%(D' =1:Bvisible*o3>+B#style.visibility<*R%(D' =+4 8?dCB0-#ppt_w/2BCB#ppt_xB*Y3>B ppt_x<*RD' =+4 8?\CB#ppt_yBCB#ppt_yB*Y3>B ppt_y<*RD' =%(D#' =%(D' =A@BBBB0B%(D' =1:Bvisible*o3>+B#style.visibility<*%(D' =+4 8?dCB0-#ppt_w/2BCB#ppt_xB*Y3>B ppt_x<*D' =+4 8?\CB#ppt_yBCB#ppt_yB*Y3>B ppt_y<*D' =%(D' =4@BBBB%(D' =1:Bvisible*o3>+B#style.visibility<*%(D' =+4 8?dCB0-#ppt_w/2BCB#ppt_xB*Y3>B ppt_x<*D' =+4 8?\CB#ppt_yBCB#ppt_yB*Y3>B ppt_y<*D{' =%(D#' =%(D' =A@BBBB0B%(D' =1:Bvisible*o3>+B#style.visibility<*%(D' =+4 8?dCB0-#ppt_w/2BCB#ppt_xB*Y3>B ppt_x<*D' =+4 8?\CB#ppt_yBCB#ppt_yB*Y3>B ppt_y<*Dz ' =%(D" ' =%(D' =A@BBBB0B%(D' =1:Bvisible*o3>+B#style.visibility<*%(D' =+4 8?dCB0-#ppt_w/2BCB#ppt_xB*Y3>B ppt_x<*D' =+4 8?\CB#ppt_yBCB#ppt_yB*Y3>B ppt_y<*D1' =4@BBBB%(D' =1:Bvisible*o3>+B#style.visibility<* %(D' =-m6Bbox(in)*<3<* D' =4@BBBB%(D' =1:Bvisible*o3>+B#style.visibility<* %(D' =+4 8?dCB0-#ppt_w/2BCB#ppt_xB*Y3>B ppt_x<* D' =+4 8?\CB#ppt_yBCB#ppt_yB*Y3>B ppt_y<* +8+0+0 +  0 d\( Ae$ z  C Xc   c e  C d^!a c "8*V  T1?/s b,$D 0H  0޽h ? 33Պ3ff3___PPT10+ELqD' = @B DW' = @BA?%,( < +O%,( < +D' =%(%(D' =%(D' =4@BBBB%(D' =1:Bvisible*o3>+B#style.visibility<* %(D' =+4 8?dCB0-#ppt_w/2BCB#ppt_xB*Y3>B ppt_x<* D' =+4 8?\CB#ppt_yBCB#ppt_yB*Y3>B ppt_y<* +;   0 n(  z  C c Qs  ^  l  C o^!F ^ @   `c1? ,4,$D  0 | 1,45 moles 0,55 moles 0,55 moles !PP!3   H  0޽h ? 33Պ3ff3___PPT10+qZD' ^= @B DD' = @BA?%,( < +O%,( < +D{' =%(D#' =%(D' =A@BBBB0B%(D' =1:Bvisible*o3>+B#style.visibility<*%(D' =+4 8?\CB#ppt_xBCB#ppt_xB*Y3>B ppt_x<*D' =+4 8?dCB1+#ppt_h/2BCB#ppt_yB*Y3>B ppt_y<*+8+0+0 +  0 L( w  ( S u^ TC  c  ( S {^!eZ ^ &x/[cH  0޽h ? 33Պ3ff3y___PPT10Y+D=' 3 = @B +#  0 H@(  z 0 C <$d IS  ^  0 C h^!veZ<$  0 ^ "8*V  T1?1  ,$D 0  T1? G,$D 0H  0޽h ? 33Պ3ff3  ___PPT10.+YD' ^= @B DM' = @BA?%,( < +O%,( < +D' =%(D`' =%(D' =A@BBBB0B%(E5' =1B B`BPB,54*3>B ppt_c='`B@BPB<*0<D' =1:Bvisible*o3>+B#style.visibility<*0<%(D' =+4 8?dCB0-#ppt_w/2BCB#ppt_xB*Y3>B ppt_x<*0<D' =+4 8?\CB#ppt_yBCB#ppt_yB*Y3>B ppt_y<*0<D' =%(D`' =%(D' =A@BBBB0B%(E5' =1B B`BPB,54*3>B ppt_c='`B@BPB<*0<D' =1:Bvisible*o3>+B#style.visibility<*0<%(D' =+4 8?dCB0-#ppt_w/2BCB#ppt_xB*Y3>B ppt_x<*0<D' =+4 8?\CB#ppt_yBCB#ppt_yB*Y3>B ppt_y<*0<D~ ' =%(D& ' =%(D' =A@BBBB0B%(E5' =1B B`BPB,54*3>B ppt_c='`B@BPB<*0D' =1:Bvisible*o3>+B#style.visibility<*0%(D' =+4 8?dCB0-#ppt_w/2BCB#ppt_xB*Y3>B ppt_x<*0D' =+4 8?\CB#ppt_yBCB#ppt_yB*Y3>B ppt_y<*0D' =4@BBBB%(D' =1:Bvisible*o3>+B#style.visibility<*%(D' =+4 8?dCB0-#ppt_w/2BCB#ppt_xB*Y3>B ppt_x<*D' =+4 8?\CB#ppt_yBCB#ppt_yB*Y3>B ppt_y<*D~ ' =%(D& ' =%(D' =A@BBBB0B%(E5' =1B B`BPB,54*3>B ppt_c='`B@BPB<*09D' =1:Bvisible*o3>+B#style.visibility<*09%(D' =+4 8?dCB0-#ppt_w/2BCB#ppt_xB*Y3>B ppt_x<*09D' =+4 8?\CB#ppt_yBCB#ppt_yB*Y3>B ppt_y<*09D' =4@BBBB%(D' =1:Bvisible*o3>+B#style.visibility<*%(D' =+4 8?dCB0-#ppt_w/2BCB#ppt_xB*Y3>B ppt_x<*D' =+4 8?\CB#ppt_yBCB#ppt_yB*Y3>B ppt_y<*+8+0+00 +vK  0 @,T(  , , S ^![Y<$  0 d  , T1?= ]: ,$D  0 , T1?9 l,$D 0H , 0޽h ? 33Պ3ff3ZHRH___PPT102H.+F|DG' ^= @B DG' = @BA?%,( < +O%,( < +D' =%(D`' =%(D' =A@BBBB0B%(E5' =1B B`BPB,54*3>B ppt_c='`B@BPB<*,D' =1:Bvisible*o3>+B#style.visibility<*,%(D' =+4 8?dCB0-#ppt_w/2BCB#ppt_xB*Y3>B ppt_x<*,D' =+4 8?\CB#ppt_yBCB#ppt_yB*Y3>B ppt_y<*,D' =%(D`' =%(D' =A@BBBB0B%(E5' =1B B`BPB,54*3>B ppt_c='`B@BPB<*,`D' =1:Bvisible*o3>+B#style.visibility<*,`%(D' =+4 8?dCB0-#ppt_w/2BCB#ppt_xB*Y3>B ppt_x<*,`D' =+4 8?\CB#ppt_yBCB#ppt_yB*Y3>B ppt_y<*,`D' =%(D`' =%(D' =A@BBBB0B%(E5' =1B B`BPB,54*3>B ppt_c='`B@BPB<*,`D' =1:Bvisible*o3>+B#style.visibility<*,`%(D' =+4 8?dCB0-#ppt_w/2BCB#ppt_xB*Y3>B ppt_x<*,`D' =+4 8?\CB#ppt_yBCB#ppt_yB*Y3>B ppt_y<*,`D' =%(D`' =%(D' =A@BBBB0B%(E5' =1B B`BPB,54*3>B ppt_c='`B@BPB<*,D' =1:Bvisible*o3>+B#style.visibility<*,%(D' =+4 8?dCB0-#ppt_w/2BCB#ppt_xB*Y3>B ppt_x<*,D' =+4 8?\CB#ppt_yBCB#ppt_yB*Y3>B ppt_y<*,D' =%(D`' =%(D' =A@BBBB0B%(E5' =1B B`BPB,54*3>B ppt_c='`B@BPB<*,@D' =1:Bvisible*o3>+B#style.visibility<*,@%(D' =+4 8?dCB0-#ppt_w/2BCB#ppt_xB*Y3>B ppt_x<*,@D' =+4 8?\CB#ppt_yBCB#ppt_yB*Y3>B ppt_y<*,@D' =%(D`' =%(D' =A@BBBB0B%(E5' =1B B`BPB,54*3>B ppt_c='`B@BPB<*,@D' =1:Bvisible*o3>+B#style.visibility<*,@%(D' =+4 8?dCB0-#ppt_w/2BCB#ppt_xB*Y3>B ppt_x<*,@D' =+4 8?\CB#ppt_yBCB#ppt_yB*Y3>B ppt_y<*,@D' =%(D`' =%(D' =A@BBBB0B%(E5' =1B B`BPB,54*3>B ppt_c='`B@BPB<*,D' =1:Bvisible*o3>+B#style.visibility<*,%(D' =+4 8?dCB0-#ppt_w/2BCB#ppt_xB*Y3>B ppt_x<*,D' =+4 8?\CB#ppt_yBCB#ppt_yB*Y3>B ppt_y<*,D' =%(D`' =%(D' =A@BBBB0B%(E5' =1B B`BPB,54*3>B ppt_c='`B@BPB<*,D' =1:Bvisible*o3>+B#style.visibility<*,%(D' =+4 8?dCB0-#ppt_w/2BCB#ppt_xB*Y3>B ppt_x<*,D' =+4 8?\CB#ppt_yBCB#ppt_yB*Y3>B ppt_y<*,D~ ' =%(D& ' =%(D' =A@BBBB0B%(E5' =1B B`BPB,54*3>B ppt_c='`B@BPB<*,D' =1:Bvisible*o3>+B#style.visibility<*,%(D' =+4 8?dCB0-#ppt_w/2BCB#ppt_xB*Y3>B ppt_x<*,D' =+4 8?\CB#ppt_yBCB#ppt_yB*Y3>B ppt_y<*,D' =4@BBBB%(D' =1:Bvisible*o3>+B#style.visibility<*,%(D' =+4 8?dCB0-#ppt_w/2BCB#ppt_xB*Y3>B ppt_x<*,D' =+4 8?\CB#ppt_yBCB#ppt_yB*Y3>B ppt_y<*,D' =%(D`' =%(D' =A@BBBB0B%(E5' =1B B`BPB,54*3>B ppt_c='`B@BPB<*,D' =1:Bvisible*o3>+B#style.visibility<*,%(D' =+4 8?dCB0-#ppt_w/2BCB#ppt_xB*Y3>B ppt_x<*,D' =+4 8?\CB#ppt_yBCB#ppt_yB*Y3>B ppt_y<*,D~ ' =%(D& ' =%(D' =A@BBBB0B%(E5' =1B B`BPB,54*3>B ppt_c='`B@BPB<*,D' =1:Bvisible*o3>+B#style.visibility<*,%(D' =+4 8?dCB0-#ppt_w/2BCB#ppt_xB*Y3>B ppt_x<*,D' =+4 8?\CB#ppt_yBCB#ppt_yB*Y3>B ppt_y<*,D' =4@BBBB%(D' =1:Bvisible*o3>+B#style.visibility<*,%(D' =+4 8?dCB0-#ppt_w/2BCB#ppt_xB*Y3>B ppt_x<*,D' =+4 8?\CB#ppt_yBCB#ppt_yB*Y3>B ppt_y<*,+8+0+,0 +  0N0   (  l  C d e`  d   C d!eZ<$ 0 d   # l1?   8A ?3?"?5 8 $D 0H  0޽h ? 33Պ3ff3xp___PPT10P.+%kD' 3 = @B D' = @BA?%,( < +O%,( < +D' =%(D' =%(DU' =A@BB4BB0B%()))D' =1:Bvisible*o3>+B#style.visibility<*U%(D' =0l9 BBzCzCBB*<3<*U%())?D' =.7 BBBBBM -0.46736 0.92887 C -0.37517 0.88508 -0.02552 0.75279 0.0908 0.66613 C 0.20747 0.57948 0.21649 0.50394 0.23177 0.40825 C 0.24705 0.31256 0.22118 0.15964 0.18264 0.09152 C 0.1441 0.02341 0.03802 0.0 0.0 0.0 *3>*B ppt_xB ppt_y=B0B<*U%())?D' =-g6B fade*<3<*UD' =%(Dp' =%(D' =4@BB4BB%(D' =1:Bvisible*o3>+B#style.visibility<* %(D' =0l9 BBzCzCBB*<3<* %())?D' =.7 BBBBBM -0.46736 0.92887 C -0.37517 0.88508 -0.02552 0.75279 0.0908 0.66613 C 0.20747 0.57948 0.21649 0.50394 0.23177 0.40825 C 0.24705 0.31256 0.22118 0.15964 0.18264 0.09152 C 0.1441 0.02341 0.03802 0.0 0.0 0.0 *3>*B ppt_xB ppt_y=B0B<* %())?D' =-g6B fade*<3<* D' =%(D' =%(DU' =A@BB4BB0B%()))D' =1:Bvisible*o3>+B#style.visibility<*Y%(D' =0l9 BBzCzCBB*<3<*Y%())?D' =.7 BBBBBM -0.46736 0.92887 C -0.37517 0.88508 -0.02552 0.75279 0.0908 0.66613 C 0.20747 0.57948 0.21649 0.50394 0.23177 0.40825 C 0.24705 0.31256 0.22118 0.15964 0.18264 0.09152 C 0.1441 0.02341 0.03802 0.0 0.0 0.0 *3>*B ppt_xB ppt_y=B0B<*Y%())?D' =-g6B fade*<3<*Y+8+0+0 +   0N0 0D(  l  C d   d   C d!:<$ 0 d H  0޽h ? 33Պ3ff3  ___PPT10c .+qD ' 3 = @B D ' = @BA?%,( < +O%,( < +D' =%(D' =%(DG' =A@BBBB0B%(D' =1:Bvisible*o3>+B#style.visibility<*2%(D' =+v4 ,0B*O3> B<*2D' =%(D' =%(DG' =A@BBBB0B%(D' =1:Bvisible*o3>+B#style.visibility<*2%(D' =+v4 ,0B*O3> B<*2D' =%(D' =%(DG' =A@BBBB0B%(D' =1:Bvisible*o3>+B#style.visibility<*%(D' =+v4 ,0B*O3> B<*+8+0+0 +  0N0 @R(   z  C d   d e  C e! eZ<$  0 e H  0޽h ? 33Պ3ff3w___PPT10W.+=D ' e= @B D ' = @BA?%,( < +O%,( < +D^' =%(D' =%(D' =A@BBBB0B%(D' =1:Bvisible*o3>+B#style.visibility<*%(D' =+4 8?dCB1+#ppt_w/2BCB#ppt_xB*Y3>B ppt_x<*D' =+4 8?dCB0-#ppt_h/2BCB#ppt_yB*Y3>B ppt_y<*D' =A@BBBB0B%(D' =1:Bvisible*o3>+B#style.visibility<*l%(D' =+4 8?dCB1+#ppt_w/2BCB#ppt_xB*Y3>B ppt_x<*lD' =+4 8?dCB0-#ppt_h/2BCB#ppt_yB*Y3>B ppt_y<*lD' =%(D+' =%(D' =A@BBBB0B%(D' =1:Bvisible*o3>+B#style.visibility<*l%(D' =+4 8?dCB1+#ppt_w/2BCB#ppt_xB*Y3>B ppt_x<*lD' =+4 8?dCB0-#ppt_h/2BCB#ppt_yB*Y3>B ppt_y<*l+8+0+0 +w%  0N0 Ph( @` z  C 0b e  d e  C 3e!Z<$ 0 b "8*VH  0޽h ? 33Պ3ff3/#'#___PPT10#.+FD"' 3 = @B Db"' = @BA?%,( < +O%,( < +D ' =%(D ' =%(D%' =A@BB4BB0B%(D' =1:Bvisible*o3>+B#style.visibility<*%(D' =0l9 BBzCzCBB*<3<*%())?D' =.7 BBBBBM -0.46736 0.92887 C -0.37517 0.88508 -0.02552 0.75279 0.0908 0.66613 C 0.20747 0.57948 0.21649 0.50394 0.23177 0.40825 C 0.24705 0.31256 0.22118 0.15964 0.18264 0.09152 C 0.1441 0.02341 0.03802 0.0 0.0 0.0 *3>*B ppt_xB ppt_y=B0B<*%())?D' =-g6B fade*<3<*D%' =A@BB4BB0B%(D' =1:Bvisible*o3>+B#style.visibility<*:%(D' =0l9 BBzCzCBB*<3<*:%())?D' =.7 BBBBBM -0.46736 0.92887 C -0.37517 0.88508 -0.02552 0.75279 0.0908 0.66613 C 0.20747 0.57948 0.21649 0.50394 0.23177 0.40825 C 0.24705 0.31256 0.22118 0.15964 0.18264 0.09152 C 0.1441 0.02341 0.03802 0.0 0.0 0.0 *3>*B ppt_xB ppt_y=B0B<*:%())?D' =-g6B fade*<3<*:D' =%(D}' =%(D%' =A@BB4BB0B%(D' =1:Bvisible*o3>+B#style.visibility<*:i%(D' =0l9 BBzCzCBB*<3<*:i%())?D' =.7 BBBBBM -0.46736 0.92887 C -0.37517 0.88508 -0.02552 0.75279 0.0908 0.66613 C 0.20747 0.57948 0.21649 0.50394 0.23177 0.40825 C 0.24705 0.31256 0.22118 0.15964 0.18264 0.09152 C 0.1441 0.02341 0.03802 0.0 0.0 0.0 *3>*B ppt_xB ppt_y=B0B<*:i%())?D' =-g6B fade*<3<*:iD' =%(D}' =%(D%' =A@BB4BB0B%(D' =1:Bvisible*o3>+B#style.visibility<*i%(D' =0l9 BBzCzCBB*<3<*i%())?D' =.7 BBBBBM -0.46736 0.92887 C -0.37517 0.88508 -0.02552 0.75279 0.0908 0.66613 C 0.20747 0.57948 0.21649 0.50394 0.23177 0.40825 C 0.24705 0.31256 0.22118 0.15964 0.18264 0.09152 C 0.1441 0.02341 0.03802 0.0 0.0 0.0 *3>*B ppt_xB ppt_y=B0B<*i%())?D' =-g6B fade*<3<*iD' =%(D}' =%(D%' =A@BB4BB0B%(D' =1:Bvisible*o3>+B#style.visibility<* %(D' =0l9 BBzCzCBB*<3<* %())?D' =.7 BBBBBM -0.46736 0.92887 C -0.37517 0.88508 -0.02552 0.75279 0.0908 0.66613 C 0.20747 0.57948 0.21649 0.50394 0.23177 0.40825 C 0.24705 0.31256 0.22118 0.15964 0.18264 0.09152 C 0.1441 0.02341 0.03802 0.0 0.0 0.0 *3>*B ppt_xB ppt_y=B0B<* %())?D' =-g6B fade*<3<* +8+0+0 +4  0N0 `( w z  C %b e`  b e  C -b!!<$ 0 b   T1? (,$D 0l A`   D 4,$D 0R   Z1?Aqb   Z1?0 ` qH  0޽h ? 33Պ3ff3O0G0___PPT10'0.+D/' 3 = @B D/' = @BA?%,( < +O%,( < +D ' =%(D ' =%(D%' =A@BB4BB0B%(D' =1:Bvisible*o3>+B#style.visibility<*%(D' =0l9 BBzCzCBB*<3<*%())?D' =.7 BBBBBM -0.46736 0.92887 C -0.37517 0.88508 -0.02552 0.75279 0.0908 0.66613 C 0.20747 0.57948 0.21649 0.50394 0.23177 0.40825 C 0.24705 0.31256 0.22118 0.15964 0.18264 0.09152 C 0.1441 0.02341 0.03802 0.0 0.0 0.0 *3>*B ppt_xB ppt_y=B0B<*%())?D' =-g6B fade*<3<*D' =4@BB4BB%(D' =1:Bvisible*o3>+B#style.visibility<* %(D' =0l9 BBzCzCBB*<3<* %())?D' =.7 BBBBBM -0.46736 0.92887 C -0.37517 0.88508 -0.02552 0.75279 0.0908 0.66613 C 0.20747 0.57948 0.21649 0.50394 0.23177 0.40825 C 0.24705 0.31256 0.22118 0.15964 0.18264 0.09152 C 0.1441 0.02341 0.03802 0.0 0.0 0.0 *3>*B ppt_xB ppt_y=B0B<* %())?D' =-g6B fade*<3<* D' =%(D}' =%(D%' =A@BB4BB0B%(D' =1:Bvisible*o3>+B#style.visibility<*%(D' =0l9 BBzCzCBB*<3<*%())?D' =.7 BBBBBM -0.46736 0.92887 C -0.37517 0.88508 -0.02552 0.75279 0.0908 0.66613 C 0.20747 0.57948 0.21649 0.50394 0.23177 0.40825 C 0.24705 0.31256 0.22118 0.15964 0.18264 0.09152 C 0.1441 0.02341 0.03802 0.0 0.0 0.0 *3>*B ppt_xB ppt_y=B0B<*%())?D' =-g6B fade*<3<*D' =%(D}' =%(D%' =A@BB4BB0B%(D' =1:Bvisible*o3>+B#style.visibility<*%(D' =0l9 BBzCzCBB*<3<*%())?D' =.7 BBBBBM -0.46736 0.92887 C -0.37517 0.88508 -0.02552 0.75279 0.0908 0.66613 C 0.20747 0.57948 0.21649 0.50394 0.23177 0.40825 C 0.24705 0.31256 0.22118 0.15964 0.18264 0.09152 C 0.1441 0.02341 0.03802 0.0 0.0 0.0 *3>*B ppt_xB ppt_y=B0B<*%())?D' =-g6B fade*<3<*D' =%(D}' =%(D%' =A@BB4BB0B%(D' =1:Bvisible*o3>+B#style.visibility<*%%(D' =0l9 BBzCzCBB*<3<*%%())?D' =.7 BBBBBM -0.46736 0.92887 C -0.37517 0.88508 -0.02552 0.75279 0.0908 0.66613 C 0.20747 0.57948 0.21649 0.50394 0.23177 0.40825 C 0.24705 0.31256 0.22118 0.15964 0.18264 0.09152 C 0.1441 0.02341 0.03802 0.0 0.0 0.0 *3>*B ppt_xB ppt_y=B0B<*%%())?D' =-g6B fade*<3<*%D% ' =%(D ' =%(D%' =A@BB4BB0B%(D' =1:Bvisible*o3>+B#style.visibility<*&e%(D' =0l9 BBzCzCBB*<3<*&e%())?D' =.7 BBBBBM -0.46736 0.92887 C -0.37517 0.88508 -0.02552 0.75279 0.0908 0.66613 C 0.20747 0.57948 0.21649 0.50394 0.23177 0.40825 C 0.24705 0.31256 0.22118 0.15964 0.18264 0.09152 C 0.1441 0.02341 0.03802 0.0 0.0 0.0 *3>*B ppt_xB ppt_y=B0B<*&e%())?D' =-g6B fade*<3<*&eDH' =4@BB4BB%()))D' =1:Bvisible*o3>+B#style.visibility<*%(D' =0l9 BBzCzCBB*<3<*%())?D' =.7 BBBBBM -0.46736 0.92887 C -0.37517 0.88508 -0.02552 0.75279 0.0908 0.66613 C 0.20747 0.57948 0.21649 0.50394 0.23177 0.40825 C 0.24705 0.31256 0.22118 0.15964 0.18264 0.09152 C 0.1441 0.02341 0.03802 0.0 0.0 0.0 *3>*B ppt_xB ppt_y=B0B<*%())?D' =-g6B fade*<3<*+8+0+0 +  0N0 pD( JD l  C 4+B#style.visibility<*Q%(D' =+v4 ,0B*O3> B<*QD' =%(D' =%(DG' =A@BBBB0B%(D' =1:Bvisible*o3>+B#style.visibility<*Q%(D' =+v4 ,0B*O3> B<*QD' =%(D' =%(DG' =A@BBBB0B%(D' =1:Bvisible*o3>+B#style.visibility<*%(D' =+v4 ,0B*O3> B<*D' =%(D' =%(DG' =A@BBBB0B%(D' =1:Bvisible*o3>+B#style.visibility<*%(D' =+v4 ,0B*O3> B<*D' =%(D' =%(DG' =A@BBBB0B%(D' =1:Bvisible*o3>+B#style.visibility<*%(D' =+v4 ,0B*O3> B<*+8+0+0 +a  0 ( JD l  C  Bb   b l  C Bb!\Zr b H  0޽h ? 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